UVA 836 - Largest Submatrix Shipu Ahamed - 01 Sep 2020 Problem PDFSolution:/****************************************************************** *** Problem : *** *** Author : Shipu Ahamed (Psycho Timekiller) *** *** E-mail : shipuahamed01@gmail.com *** *** University : BUBT,Dept. of CSE *** *** Team : BUBT_Psycho *** *** My Blog : http://shipuahamed.blogspot.com *** *** Facebook : http://www.facebook.com/DeesheharaShipu *** ******************************************************************/ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define pi 2*acos(0.0) #define all(v) v.begin(),v.end() //input #define si(t) scanf("%d",&t) #define sl(t) scanf("%lld",&t) #define sf(t) scanf("%f",&t) #define sd(t) scanf("%lf",&t) #define sc(c) scanf("%c",&c) #define sii(a,b) scanf("%d%d",&a,&b) #define sll(a,b) scanf("%lld%lld",&a,&b) //Output #define P(a) printf("%d\n",a) #define PL(a) printf("%lld\n",a) #define PF(a) printf("%f\n",a) #define PD(a) printf("%lf\n",a) #define PS(a) printf("%s\n",a) #define PSN(a) printf("%s ",a) #define PN(a) printf("%d ",a) #define PLN(a) printf("%lld ",a) #define PFN(a) printf("%f ",a) #define PDN(a) printf("%lf ",a) #define PP(a,b) printf("%d %d\n",a,b) #define PPN(a,b) printf("%d %d ",a,b) #define PPL(a,b) printf("%lld %lld\n",a,b) #define PPLN(a,b) printf("%lld %lld ",a,b) #define CP(a) cout< vi; typedef vector vll; typedef vector vs; typedef set si; typedef set ss; typedef map mii; typedef map mll; typedef map msi; typedef map mci; template string toString( T Number ){stringstream st;st << Number;return st.str();} template T SOD(T n) {__typeof(n) sum=0;for(__typeof(n) i=1;i*i<=n;i++)sum+=(n%i)?0:((i*i==n)?i:i+n/i);return sum;} //For Define #define forab(i,a,b) for(__typeof(b) i=(a);i<=(b);i++) #define for0(i,n) forab(i,0,(n)-1) #define for1(i,n) forab(i,1,n) #define rforab(i,b,a) for(__typeof(b) i=(b);i>=(a);i--) #define rfor0(i,n) rforba(i,(n)-1,0) #define rfor1(i,n) rforba(i,n,1) #define forstl(i,s) for(__typeof((s).end()) i=(s).begin(); i != (s).end(); i++) //Debug #define dbg(x) cout << #x << " -> " << (x) << endl; #define dbgsarr(i,a) cout<<#a<<"["< "< "< "<>p ; return p;} ll pow(ll a,ll b, ll m) { ll res = 1; while(b) { if(b & 1) { res = ( (res % m) * (a % m) ) %m ; } a= ((a%m) * (a%m)) %m; b >>= 1; } return res; } ll modInverse(ll a, ll m){return pow(a,m-2,m);} ////============ CONSTANT ===============//// #define mx7 10000007 #define mx6 1000006 #define mx5 100005 #define inf 1<<30 //infinity value #define eps 1e-9 #define mx (100010) #define mod 1000000007 ////=====================================//// struct zeone { int one=0,zero=0; }; int main() { int t; si(t); while(t--) { string s[30]; cin>>s[0]; int n=sz(s[0]); zeone cs[50][50]; for0(i,n) { if(s[0][i]=='0') { cs[1][i+1].zero = cs[1][i].zero+1; cs[1][i+1].one = cs[1][i].one; } else { cs[1][i+1].one = cs[1][i].one+1; cs[1][i+1].zero = cs[1][i].zero; } // PN(cs[1][i+1].one); } // nl; for1(i,n-1) { cin>>s[i]; for0(j,n) { if(s[i][j]=='0') { cs[i+1][j+1].zero = cs[i][j+1].zero + cs[i+1][j].zero - cs[i][j].zero +1; cs[i+1][j+1].one = cs[i][j+1].one + cs[i+1][j].one - cs[i][j].one; } else { cs[i+1][j+1].zero = cs[i][j+1].zero + cs[i+1][j].zero - cs[i][j].zero; cs[i+1][j+1].one = cs[i][j+1].one + cs[i+1][j].one - cs[i][j].one+1; } // PN(cs[i+1][j+1].one); } // nl; } // nl; // for0(i,n) // { // cout<=p) { res.zero = p; p = ( cs[i][j].one - (cs[i][l-1].one + cs[k-1][j].one) ) + cs[k-1][l-1].one; if(res.onehttps://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/836/836.cpp