UVA 10168 - Summation of Four Primes Shipu Ahamed - 01 Sep 2020 Problem PDFSolution:/****************************************************************** *** Problewm : *** *** Author : Shipu Ahamed (Psycho Timekiller) *** *** E-mail : shipuahamed01@gmail.com *** *** University : BUBT,Dept. of CSE *** *** Team : BUBT_Psycho *** *** My Blog : http://shipuahamed.blogspot.com *** *** Facebook : http://www.facebook.com/DeesheharaShipu *** ******************************************************************/ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define sc scanf #define pf printf #define ll long long #define pi 2*acos(0.0) #define ull unsigned long long #define all(v) v.begin(),v.end() #define sii(t) scanf("%d",&t) #define sll(t) scanf("%lld",&t) #define ssii(a,b) scanf("%d%d",&a,&b) #define ssll(a,b) scanf("%lld%lld",&a,&b) #define Case(no) printf("Case %d:",++no) #define nl puts("") #define P(a) printf("%d\n",a) #define PL(a) printf("%lld\n",a) #define PN(a) printf("%d ",a) #define PLN(a) printf("%lld ",a) #define ff first #define se second #define pb push_back #define ST(v) sort(all(v)) #define gcd(a,b) __gcd(a,b) #define lcm(a,b) (a*(b/gcd(a,b))) #define max3(a,b,c) max(a,max(b,c)) #define min3(a,b,c) min(a,min(b,c)) #define maxall(v) *max_element(all(v)) #define minall(v) *min_element(all(v)) #define cover(a,d) memset(a,d,sizeof(a)) #define popcount(i) __builtin_popcount(i) //count one #define input freopen("in.txt","r",stdin) #define output freopen("out.txt","w",stdout) #define un(v) ST(v), (v).earse(unique(all(v)),v.end()) #define common(a,b) ST(a), ST(b), a.erase(set_intersection(all(a),all(b),a.begin()),a.end()) #define uncommon(a,b) ST(a), ST(b), a.erase(set_symmetric_difference(all(a),all(b),a.begin()),a.end()) ////============ CONSTANT ===============//// #define mx (10000010) #define Max 1000000 //infinity value #define eps 1e-9 #define mod 10007 ////=====================================//// bool prime[mx]; int p[mx],k=1; void sieve() { prime[1]=false; p[0]=2;oi for(int i=2;i<=mx;i+=2) prime[i]=true; int n=sqrt(mx); for(int i=3;i<=n;i=i+2) { if(!prime[i]) { p[k++]=i for(int j=2*i;j<=mx;j+=i) { prime[j]=true; } } } } void fourprime(int n) { int a,i,f=0; for(i=0;ihttps://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/10168/10168.cpp