UVA 11137 - Ingenuous Cubrency Shipu Ahamed - 01 Sep 2020 Problem PDFSolution:/****************************************************************** *** Author : Shipu Ahamed (Psycho Timekiller) *** *** E-mail : shipuahamed01@gmail.com *** *** University : BUBT,Dept. of CSE *** *** Team : BUBT_HIDDEN *** *** My Blog : http://shipuahamed.blogspot.com *** *** Facebook : http://www.facebook.com/DeesheharaShipu *** ******************************************************************/ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define sc scanf #define pf printf #define ll long long #define pi 2*acos(0.0) #define ull unsigned long long #define all(v) v.begin(),v.end() #define sii(t) scanf("%d",&t) #define sll(t) scanf("%lld",&t) #define ssii(a,b) scanf("%d%d",&a,&b) #define ssll(a,b) scanf("%lld%lld",&a,&b) #define Case(no) printf("Case %d: ",++no) #define P(a) printf("%d\n",a) #define PL(a) printf("%lld\n",a) #define PN(a) printf("%d",a) #define PLN(a) printf("%lld",a) #define ff first #define se second #define pb push_back #define ST(v) sort(all(v)) #define gcd(a,b) __gcd(a,b) #define lcm(a,b) (a*(b/gcd(a,b))) #define max3(a,b,c) max(a,max(b,c)) #define min3(a,b,c) min(a,min(b,c)) #define maxall(v) *max_element(all(v)) #define minall(v) *min_element(all(v)) #define cover(a,d) memset(a,d,sizeof(a)) #define popcount(i) __builtin_popcount(i) //count one #define input freopen("in.txt","r",stdin) #define output freopen("out.txt","w",stdout) #define un(v) ST(v), (v).earse(unique(all(v)),v.end()) #define common(a,b) ST(a), ST(b), a.erase(set_intersection(all(a),all(b),a.begin()),a.end()) #define uncommon(a,b) ST(a), ST(b), a.erase(set_symmetric_difference(all(a),all(b),a.begin()),a.end()) ////============ CONSTANT ===============//// #define mx (2000010) #define inf (1<<30) //infinity value #define eps 1e-9 #define mod 1000000007 ////====================================//// int main() { ll coin[100],way[20000]={0},i,j,a,p; for(i=1,j=0;i<22;i++) { coin[j++]=i*i*i; } way[0]=1; for(i=0;i<22;i++) { for(j=coin[i];j<=10010;j++) { way[j]+=way[j-coin[i]]; } } while(sii(a)==1) { PL(way[a]/2); } return 0; } https://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/11137/11137.cpp