UVA 11220 - Decoding the message. UVA • Sep 1, 2020 Problem PDFSolution:#include #include #include #include #include #include #include #include #include #include #include #include #define ll long long #define sc scanf #define pf printf #define Pi 2*acos(0.0) using namespace std; int main() { char s[40000],b[40000]; int t,no=0; sc("%d",&t); getchar(); int i=0; while(t--) { for(i=0;;i++) { gets(s); } int j=0; b[j++]=s[j]; for(int i=1;ihttps://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/11220/11220.cpp Tags UVA Competitive Programming Shipu Ahamed Recommended for you UVA UVA 913 - Joana and the Odd Numbers 4 years ago • 1 min read UVA UVA 871 - Counting Cells in a Blob 4 years ago • 3 min read UVA UVA 866 - Intersecting Line Segments 4 years ago • 3 min read