UVA 113 - Power of Cryptography UVA • Sep 1, 2020 Problem PDFSolution:#include #include int main() { double n,p; double s; while(scanf("%lf %lf",&n,&p)==2) { s=pow(p,1/n); printf("%.0lf\n",s); } return 0; } https://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/113/113.cpp Tags UVA Competitive Programming Shipu Ahamed Recommended for you UVA UVA 913 - Joana and the Odd Numbers 4 years ago • 1 min read UVA UVA 871 - Counting Cells in a Blob 4 years ago • 3 min read UVA UVA 866 - Intersecting Line Segments 4 years ago • 3 min read