UVA 11541 - Decoding UVA • Sep 1, 2020 Problem PDFSolution:#include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define ll long long #define sc scanf #define pf printf #define Pi 2*acos(0.0) int main() { int t,no=0; char s[1000],c; sc("%d",&t); getchar(); while(t--) { gets(s); int l=strlen(s); pf("Case %d: ",++no); for(int i=0;i='A'&&s[i]<='Z') c=s[i]; else if(s[i]>='0'&&s[i]<='9') { p+=s[i]-'0'; i++; while(s[i]>='0'&&s[i]<='9') { p=p*10+s[i]-'0'; i++; } i--; for(int j=0;jhttps://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/11541/11541.cpp Tags UVA Competitive Programming Shipu Ahamed Recommended for you UVA UVA 913 - Joana and the Odd Numbers 4 years ago • 1 min read UVA UVA 871 - Counting Cells in a Blob 4 years ago • 3 min read UVA UVA 866 - Intersecting Line Segments 4 years ago • 3 min read