UVA 294 - Divisors Shipu Ahamed - 01 Sep 2020 Problem PDFSolution:/************************************* ******** Team : BUBT_HIDDEN ********** ************************************** *********** Shipu Ahamed ************* *************************************/ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define sc scanf #define pf printf #define ll long long #define pi 2*acos(0.0) #define ff first #define se second #define inf (1<<30) //infinity value #define pb push_back #define mod 1000000007 #define ST(v) sort(v.begin(),v.end()) #define cover(a,d) memset(a,d,sizeof(a)) #define input freopen("in.txt","r",stdin) #define output freopen("out.txt","w",stdout) #define maxall(v) *max_element(v.begin(),v.end()) #define minall(v) *min_element(v.begin(),v.end()) #define un(v) ST(v), v.erase(unique(v.begin(),v.end()),v.end()) using namespace std; int main() { // input; // output; long long lwr,upp,t,j,i,divisor,Max,num; cin>>t; while(t--) { sc("%lld %lld",&lwr,&upp); Max=0; if(lwr==1&&upp==0) { printf("Between 1 and 1, 0 has a maximum of 2 divisors.\n"); continue; } for(i=lwr;i<=upp;i++) { divisor=0; int p=sqrt(i); for(j=1;j<=p;j++){ if(i%j==0){ divisor++; if(i/j!=j){ divisor++; } } // printf("%lld has a maximum of %lld divisors.\n",i,divisor); if(Maxhttps://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/294/294.cpp