UVA 455 - Periodic Strings UVA • Sep 1, 2020 Problem PDFSolution:/****************************************************************** *** Problem : *** *** Author : Shipu Ahamed (Psycho Timekiller) *** *** E-mail : [email protected] *** *** University : BUBT,Dept. of CSE *** *** Team : BUBT_Psycho *** *** My Blog : http://shipuahamed.blogspot.com *** *** Facebook : http://www.facebook.com/DeesheharaShipu *** ******************************************************************/ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define pi 2*acos(0.0) #define all(v) v.begin(),v.end() #define CP(a) cout< vi; typedef vector vll; typedef vector vs; typedef set si; typedef set ss; typedef map mii; typedef map mll; typedef map msi; typedef map mci; template string toString( T Number ){stringstream st;st << Number;return st.str();} template T SOD(T n) {__typeof(n) sum=0;for(__typeof(n) i=1;i*i<=n;i++)sum+=(n%i)?0:((i*i==n)?i:i+n/i);return sum;} //For Define #define forab(i,a,b) for(__typeof(b) i=(a);i<=(b);i++) #define for0(i,n) forab(i,0,(n)-1) #define for1(i,n) forab(i,1,n) #define rforab(i,b,a) for(__typeof(b) i=(b);i>=(a);i--) #define rfor0(i,n) rforab(i,(n)-1,0) #define rfor1(i,n) rforab(i,n,1) #define forstl(i,s) for(__typeof((s).end()) i=(s).begin(); i != (s).end(); i++) //File input/output #define input freopen("in.txt","r",stdin) #define output freopen("out.txt","w",stdout) //upper bound and lower bound #define LB(a,value) (lower_bound(all(a),value)-a.begin()) #define UB(a,value) (upper_bound(all(a),value)-a.begin()) //Test Case & New line #define Case(no) cout<<"Case "<<++no<<": " #define nl puts("") int stringconvert(string s){int p; istringstream st(s); st>>p ; return p;} ll pow(ll a,ll b, ll m) { ll res = 1; while(b) { if(b & 1) { res = ( (res % m) * (a % m) ) %m ; } a= ((a%m) * (a%m)) %m; b >>= 1; } return res; } ll modInverse(ll a, ll m){return pow(a,m-2,m);} ////============ CONSTANT ===============//// #define mx7 10000007 #define mx6 1000006 #define mx5 100005 #define inf 1<<30 //infinity value #define eps 1e-9 #define mx (100010) #define mod 1000000007 ////=====================================//// string p; int pre[mx6],m; void prefix() { int q=0; pre[1]=0; forab(i,2,m) { while(q>0 && p[q+1]!=p[i]) { q=pre[q]; } if(p[q+1]==p[i]) q++; pre[i]=q; } } int main() { ios_base::sync_with_stdio(0);cin.tie(); int t,no=0; cin>>t; while(t--) { cin>>p; m=sz(p); p=" "+p; prefix(); int res=m-pre[m]; if(m%res==0) { CP(res); } else { CP(m); } if(t) cout<<"\n"; } return 0; } https://github.com/Shipu/OnlineJudgeProblemSolutionWithCPlusPlus/tree/master/uva/455/455.cpp Tags UVA Competitive Programming Shipu Ahamed Recommended for you UVA UVA 913 - Joana and the Odd Numbers 4 years ago • 1 min read UVA UVA 871 - Counting Cells in a Blob 4 years ago • 3 min read UVA UVA 866 - Intersecting Line Segments 4 years ago • 3 min read